A car is parked on a cliff overlooking the sea on an incline that provides an angle of 17 degrees below the horizontal. The negligent driver leaves the automobile in neutral, and the emergency brakes are defective. The auto rolls from rest down the incline with a constant acceleration of 4.8 m/s 2 and travels 43 m to the edge of the cliff. The cliff is 30 m over the sea. (a)**How long is the auto in the air**? The acceleration of gravity is 9.81 m/s 2 . Answer in systems of s.

You are watching: A car is parked on a cliff overlooking the ocean on an incline

(b) What is the car’s position relative to the base of the cliff as soon as the auto lands in the ocean? Answer in systems of m.

Follow • 1

Add comment

More

Report

## 1 Expert Answer

Best Newest OldestBy: BestNewestOldest

Tutor

4.9 (77)

Effective, patient, knowledgeable math tutor who can help you succeed

About this tutor›

About this tutor›

Bio

At the bottom of the incline v2= u2 + 2as,,, u=0. a = 4.8, s = 43, so v = 20.3 m/s

So the horizontal velocity at that suggest will be 20.3 cos 17 = 19.4 m/s, and also the vertical velocity downward 20.3 sin 17 = 5.94 m/s

To discover the moment in this air, this is the time it takes the car to loss 30 m.

s = ut + 0.5 a t2

30 = 5.94 t + 0.5 x 9.81 t2

4.905 t2 - 5.94t - 30 = 0

offering t = 3.2 s from graphing it and using trace

So horizontal distance travelled = 3.2 x 19.4 = 62.08 m

Mike

Upvote • 0 Downvote

Add comment

More

Report

## Still searching for help? Get the right answer, fast.

Ask a question for complimentary

Get a free answer to a quick trouble. Most inquiries answered within 4 hours.

OR

Find an Online Tutor Now

Choose an professional and fulfill digital. No packperiods or subscriptions, pay just for the time you require.

¢ € £ ¥ ‰ µ · • § ¶ ß ‹ › « » > ≤ ≥ – — ¯ ‾ ¤ ¦ ¨ ¡ ¿ ˆ ˜ ° − ± ÷ ⁄ × ƒ ∫ ∑ ∞ √ ∼ ≅ ≈ ≠ ≡ ∈ ∉ ∋ ∏ ∧ ∨ ¬ ∩ ∪ ∂ ∀ ∃ ∅ ∇ ∗ ∝ ∠ ´ ¸ ª º † ‡ À Á Â Ã Ä Å Æ Ç È É Ê Ë Ì Í Î Ï Ð Ñ Ò Ó Ô Õ Ö Ø Œ Š Ù Ú Û Ü Ý Ÿ Þ à á â ã ä å æ ç è é ê ë ì í î ï ð ñ ò ó ô õ ö ø œ š ù ú û ü ý þ ÿ Α Β Γ Δ Ε Ζ Η Θ Ι Κ Λ Μ Ν Ξ Ο Π Ρ Σ Τ Υ Φ Χ Ψ Ω α β γ δ ε ζ η θ ι κ λ μ ν ξ ο π ρ ς σ τ υ φ χ ψ ω ℵ ϖ ℜ ϒ ℘ ℑ ← ↑ → ↓ ↔ ↵ ⇐ ⇑ ⇒ ⇓ ⇔ ∴ ⊂ ⊃ ⊄ ⊆ ⊇ ⊕ ⊗ ⊥ ⋅ ⌈ ⌉ ⌊ ⌋ 〈 〉 ◊

### RELATED TOPICS

Math Science Chemisattempt Physics Work Graph Acceleration Time Variables Velocity ... Ap Chemisattempt Physics B Physics C Math Word Problem Kinetic Energy Energy Physics Vectors Newton's Universal Law Of Gravitation Constant Physics Science

### RELATED QUESTIONS

a steel sphere is dropped onto a tough floor from a elevation of 1.30 m and rebounds to a height of 1.25 m. calculate its velocity just prior to it strikes the floorAnswers · 1

Three high institution physics problems please help!Answers · 1

A rocket skateboard of mass 3.00 kg has an initial velocity of (5.00, 2.50) m/s. A net force of (3.40, 2.67) N is applied to it for 10.0 s. what's the velocity?Answers · 1

How long does the pinball sit in its area?Answers · 1

An object moves through a consistent acceleration of 5 m/s squared which of the following statements is trueAnswers · 1

### RECOMMENDED TUTORS

William S.

5.0 (285)Scott K.

5 (159)Richard P.

5.0 (170)See more tutors

### find an virtual tutor

### connected lessons

Downpack our complimentary app

A connect to the app was sent to your phone.

See more: How To Turn On Ok Google S7 Edge, Samsung S7 Edge

Please administer a valid phone number.

Google Play App Store

Get to know us

Discover with us

Work via us

Downfill our totally free application

Google Play App Store

Let’s keep in touch

Need more help?

Find Out more around just how it works

Best in organization considering that 2005

Tutors by Subject

Tutors by Location

Sitemap Terms of Use Privacy Policy

© 2005 - 2021 neurosoup.org, Inc, a division of IXL Learning - All Rights Reserved |