A male starts walking north at 3 ft/s indigenous a point P. 5 minutes later on a woman starts walking southern at 4 ft/s from a point 500 ft due east of P. At what rate (in ft/s) room the people moving apart 15 minutes after the mrs starts walking? (Round your answer to two decimal places.)
Let t be the time in minutes after the woman starts walking.
You are watching: A man starts walking north at 4 ft/s
Then if us say the origin (0,0) is at P
At time t
The guy is in ~ (0, 3 (5+t))
The mrs is at (-4t, -500)
If s is distance between them, climate s2 = (-4t)2 + (15+3t+500)2 (*)
Using the distance formula.
Differentiating v respect to t
2s ds/dt = 2 (-4t) (-4) + 2 (15 + 3t+500) (3) (**)
So when t = 15
Calculate s utilizing (*)Find ds/dt utilizing (**)Sorry, typo. Mrs is in ~ (500, -4t). So s^2 = 500^2 + <15 + 3t +4t>^2, therefore 2s ds/dt = 2 (15 + 7t) (7).
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