A MAN STARTS WALKING NORTH AT 4 FT/S

A male starts walking north at 3 ft/s indigenous a point P. 5 minutes later on a woman starts walking southern at 4 ft/s from a point 500 ft due east of P. At what rate (in ft/s) room the people moving apart 15 minutes after the mrs starts walking? (Round your answer to two decimal places.)



Let t be the time in minutes after the woman starts walking.

You are watching: A man starts walking north at 4 ft/s

Then if us say the origin (0,0) is at P

At time t

The guy is in ~ (0, 3 (5+t))

The mrs is at (-4t, -500)

If s is distance between them, climate s2 = (-4t)2 + (15+3t+500)2 (*)

Using the distance formula.

Differentiating v respect to t

2s ds/dt = 2 (-4t) (-4) + 2 (15 + 3t+500) (3) (**)

So when t = 15

Calculate s utilizing (*)Find ds/dt utilizing (**)

Sorry, typo. Mrs is in ~ (500, -4t). So s^2 = 500^2 + <15 + 3t +4t>^2, therefore 2s ds/dt = 2 (15 + 7t) (7).
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