Why is occupational a state function? my instructor provided the example of lifting a box straight up 1 m vs moving it up and down and also all around the room with the net activity being increase 1 m. Why is there any difference in the work between these 2 situations since the displacement of the box is the very same in each situation (ie. Shouldn't the net occupational be the same in each case)?
FreeTheBeeRegular MemberPosts: 87Mole Snacks: +12/-1

It is not. Job-related depends top top the path taken. The potential energy distinction of the box will count on the position before and also after lifting it. The amount of occupational done on the box counts on the route from the early to last position.

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Bob SacamanoRegular MemberPosts: 63Mole Snacks: +1/-3
What carry out you average by "the job-related done top top the box"?Say if friend raise the box, you are doing positive work-related on the box and gravity is doing an adverse work on the box. What is the occupational done top top the box?
when you press the box you do work on it.when the box pushes you the box does job-related on you.both statements room true in reverse if you move the indications (i.e. Negative work)the net job-related done on package by all sources (e.g. You, gravity, the wind) is provided by the equation:w = F*dwork amounts to force(s) times street movedwhereF = m*aforce equals mass time acceleration
Moving the box horizontally will certainly not give any type of net work. It is true the you accelerate the box to start it relocating horizontally but the in ~ the last position the box is static. As such when you stop the crate its acceleration will be negative and an adverse work will certainly be excellent on the box resulting in the net job-related done in the horizontal aircraft to be zero.Work will be done in the upright plane. However that job-related will be equal to the difference in potential power of package which is a state function.So.... How is occupational a state function?Note: I have actually neglected every frictional forces in my logic.
The meaning work done in physics is force times displacement. It doesn't matter how you get that final displacement of 1m. I.e., also if you have actually moved the box through a street of 1000 light years up and down and also finally up by 1m, the net displacement is just 1m.Work, through the way, is no a state duty always. It is a state duty only in a conservative field. I.e, when the force creating the ar is conservative in nature.
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BorekMr. PHAdministratorDeity MemberPosts: 26728Mole Snacks: +1732/-403Gender: ns am well-known to be occasionally wrong.
You were currently told at the an extremely beginning - job-related is no a state function.In very details case of gravitational fields, if every little thing else is neglected, potential power of the human body depends just on the state - that is, street from the massive center. Hence potential energy is a state role in this case. As alters in the potential power will be similar to the work-related done, job-related will additionally depend only on the state (position), so it will certainly behave choose a state function. However that's just in a an extremely specfic case, in basic work is no a role of state, together amount the work compelled to move body from one location to another depends ~ above the path.
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In thermodynamics, occupational done in a reversible process is a state function. Work-related done in an irreversible procedure depends on the method the state is attained.

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"Destiny is not a issue of chance; yet a issue of choice. The is not a thing to be waited for; the is a thing to be achieved." - wilhelm Jennings Bryan
BorekMr. PHAdministratorDeity MemberPosts: 26728Mole Snacks: +1732/-403Gender: i am known to be sometimes wrong.
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