The trouble states the we have actually aqueous remedies which way the solvent iswater. This way the value of Kf is thesame for all the given solutions.
You are watching: Rank these aqueous solutions from lowest freezing point to highest freezing point.
Therefore, ΔTf will simply depend top top theosmolality of every solution, offered by:
Ahigher osmolality or concentrationwill an outcome in alower freeze point.
I. 0.40 mC2H6O2
C2H6O2 is anon-electrolyte, which meansi = 1.
Solving for osmolality:
Osmolality = (1)(0.40) =0.40
II. 0.20 m Na3PO4
Na3PO4 is anelectrolyte, dissociating into 3 Na+ and PO43–, i m sorry meansi = 4.
Solving because that osmolality:
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Rank these aqueous services from lowest freezing allude to greatest freezing point.
I. 0.40 m C2H6O2
II. 0.20 m Na3PO4
III. 0.30 m KNO3
IV. 0.20 m C6H12O6
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