Did you recognize from the number 132, if you take the sum of all the 2-digit numbers, you get 12 + 13 + 21 + 23 + 31 + 32 = 132 making it the smallest number among 264, 396, and 35964 via this property? In this lesboy, we will certainly find the factors of 132, prime factors of 132, and also factors of 132 in pairs in addition to solved examples for a much better knowledge.

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**Factors of 132:**1, 2, 3, 4, 6, 11, 12, 22, 33, 44, 66, and 132

**Prime Factorization of 132:**132 = 2 × 2 × 3 × 11

1. | What Are the Factors of 132? |

2. | How to Calculate Factors of 132? |

3. | Factors of 132 by Prime Factorization |

4. | Factors of 132 in Pairs |

5. | FAQs on Factors of 132 |

## What are the Factors of 132?

Factors of a number are the numbers that divide the provided number specifically without any kind of remainder. Factors of 132 are 1, 2, 3, 4, 6, 11, 12, 22, 33, 44, 66, and also 132.**So,132 is a compowebsite number as it has actually even more components other than 1 and also itself.**

**How to Calculate the Factors of 132?**

**We deserve to usage different techniques like divisibility test, prime factorization, and the upside-down division method to calculate the factors of 132. We express 132 as a product of its prime factors in the prime factorization strategy and we divide 132 via its divisors in the division method. Let us check out which numbers divide 132 specifically without a remainder.**

**Hence, the factors of 132 are 1, 2, 3, 4, 6, 11, 12, 22, 33, 44, 66, and 132.**

**Explore determinants using illustrations and interactive examples.**

## Factors of 132 by Prime Factorization

We deserve to perform prime factorization of any kind of number by:

Upside-down department methodFactor tree method### Prime Factorization by Division Method

The upside-dvery own division obtained its name because the department symbol is flipped upside down.

STEP 1: By utilizing divisibility rules, we uncover out the smallest precise prime divisor (factor) of the offered number. Here, 132 is an also number. So it is divisible by 2. In other words, 2 divides 132 through no remainder. Therefore 2 is the smallest prime element of 132.STEP 2: We divide the offered number by its smallest factor various other than 1 (prime factor), 132/2 = 66STEP 3: We then uncover the prime components of the obtained quotient.Repeat Tip 1 and also Tip 2 till we acquire a prime number as a quotient. In the last step, 33 is the quotient, 33/3= 11. 11 is the quotient here, so we stop the process as 11 is a prime number.Thus 132 = 2 × 2 × 3 × 11.

### Prime Factorization by Factor Tree Method

First, we identify the 2 factors that offer 132. 132 is the root of this variable tree.

132 = 2 × 66

Here, 66 is an even composite number, so it have the right to be additionally factorized.

66 = 2 × 66

We continue this procedure until we are left through just prime numbers, i.e., till we cannot even more element the acquired numbers.

Basically, we branch out 132 right into its prime determinants. Factor tree is not unique for a given number.

Instead of expushing 132 as 2 × 66, we can express 132 as 4 × 33 or 3 × 44

Here is an easy activity to try it on your own, rather of 2 × 66, if we had actually offered 3 × 44, do you think we will certainly obtain the very same factor tree?

Can you attract the variable tree via 3 and 44 as the branches?

## Factors of 132 in Pairs

Factor pairs are the 2 numbers that, as soon as multiplied, give the number 132.

Factor Pairs of 132Notation1 ×132 | (1, 132) |

2 × 66 | (2, 66) |

3 × 44 | (3, 44) |

4 × 33 | (4, 33) |

6 × 22 | (6, 22) |

11 × 12 | (11, 12) |

**We have the right to have actually negative factors also for a offered number.**As the product of 2 negative numbers is positive (- × - = +), therefore (-1, -132), (-2, -66), and also (-3, -44), and so on, are likewise aspect pairs of 132

But, for currently, let us emphasis on the positive components in this post. With determinants, we are just looking for entirety numbers that are equal to or much less than the original number.

**Important Notes:**

**Think Tank:**

**Example 1: **Huia renders 132 bran biscuits for the school gala. She desires to put them in packets that each have the same number of biscuits, but she doesn’t want any kind of left over. What number of equal packets can Huia make up?

**Solution:**

We need to discover various possible methods of packing.Total number of biscuits = Number of packets × Number of biscuits in each packetHence, 132 = p × bFor that, we have to list out the aspect pairs of 132

132 = 1 × 132, i.e, 132 packets with 1 biscuit in each.

132 = 2 × 66, i.e, 66 packets with 2 biscuits in each.

132 = 3 × 44, i.e, 44 packets with 3 biscuits in each.

132 = 4 × 33, i.e, 33 packets through 4 biscuits in each.

132 = 6 × 22, i.e, 22 packets via 6 biscuits in each.

132 = 11 × 12, i.e, 12 packets with 11 biscuits in each.

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This would certainly work the other means round as well, favor 11 packets via 12 biscuits in each. Hence, there are 12 ways of packing feasible.